Here is this week's riddle:
Riddle #71: [via]*
Inside of a dark closet are five hats: three blue and two red. Knowing this, three smart men go into the closet, and each selects a hat in the dark and places it unseen upon his head. Once outside the closet, no man can see his own hat. The first man looks at the other two, thinks, and says, “I cannot tell what colour my hat is.” The second man hears this, looks at the other two, and says, “I cannot tell what colour my hat is either.” The third man is blind. The blind man says, “Well, I know what colour my hat is.” What colour is his hat?
*This riddle comes from the same site as last week's riddle so you must resist the temptation to look at the answer.
Good luck and remember to share your ideas in the comments. Read more for the solution to last week's riddle.
Here is the solution to last week's riddle:
Riddle #70: [via]
One cheating husband:
If only one man were cheating then clearly his wife would work this out on the first day as she would have known that no other husbands were cheating and so the cheating husband must be hers.
Two cheating husbands:
Consider this from the point of view of Bettie one of the wives (Bettie and Anna) who are being cheated on, though all their positions are infact the same. Bettie would be aware that Anna's husband was cheating on her and would therefore expect that she would deduce this on the first day as in the example above, because this does not happen Bettie knows that Anna is also aware of a cheating husband. Since Betty was not aware of this it must be her husband who is cheating. Anna will go through the same thought process and so two men will be thrown out on the 2nd day.
Three cheating husbands:
Charlotte will be aware Anna and Bettie's cheating husbands and expect the process to be solved as in the example above on the 2nd day, when this doesn't happen she will know that Anna and Bettie must also be aware of 2 cheating husbands and will hence chuck out her fella on the third day. Anna and Betty will think and do the same.
N cheating husbands:
Any of the wives being cheated on will be aware of N-1 cheating husbands and expect the process to be solved on the (N-1)th day, when this doesn't happen they all become aware that all the other wives that they thought were being cheated were all under the same impression and hence they must be the Nth cheated on wife. Hence on the Nth day N wives throw out N husbands.
Hence the answer, on the 10th day:
10 men are thrown out.
(Kudos to Jason for getting this riddle correct!)
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